What is factor y^{2x}-y^x-20 ?

The solution to factor y^{2x}-y^x-20 is (y^x+4)(y^x-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor y^{2x}-y^x-20

factor

y^{2 x} - y^{x} - 20

(y^{x} + 4) (y^{x} - 5)

Solution steps

y^{2 x} - y^{x} - 20

Apply exponent rule:

a^{b c} = (a^{b})^{c}

y^{2 x} = (y^{x})^{2}

= (y^{x})^{2} - y^{x} - 20

Break the expression into groups

= ((y^{x})^{2} + 4 y^{x}) + (- 5 y^{x} - 20)

Factor out

y^{x}

from

(y^{x})^{2} + 4 y^{x} : y^{x} (y^{x} + 4)

Factor out

- 5

from

- 5 y^{x} - 20 : - 5 (y^{x} + 4)

= y^{x} (y^{x} + 4) - 5 (y^{x} + 4)

Factor out common term

y^{x} + 4

= (y^{x} + 4) (y^{x} - 5)

5 x^{2} + 2 x + 8 = 0

(x^{\frac{1}{3}})^{5}

x^{2} + 12 x - 9 = 0

j + 7 = 23

3 [m - 7] + 9 > - 30

What is factor y^{2x}-y^x-20 ?
The solution to factor y^{2x}-y^x-20 is (y^x+4)(y^x-5)