What is (-1+5i)/(3-2i) ?

The solution to (-1+5i)/(3-2i) is -1+i

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simplify (-1+5i)/(3-2i)

simplify

\frac{- 1 + 5 i}{3 - 2 i}

- 1 + i

Solution steps

\frac{- 1 + 5 i}{3 - 2 i}

Multiply by the conjugate

\frac{3 + 2 i}{3 + 2 i}

= \frac{( - 1 + 5 i ) ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )}

Simplify

\frac{( - 1 + 5 i ) ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )} : \frac{- 13 + 13 i}{13}

= \frac{- 13 + 13 i}{13}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 13}{13} + \frac{13}{13} i

Simplify

\frac{- 13}{13} + \frac{13}{13} i : - 1 + i

= - 1 + i

e^{- 4 l n (3)}

x^{4} + 8 x^{3} + 8 x^{2} - 72 x - 153

\frac{3}{4} = \frac{x}{12}

n^{2} - 4 n - 21

\frac{21}{- 7}