What are the solutions to the equation 6x(x-1)=21-x ?

The solutions to the equation 6x(x-1)=21-x are x= 7/3 ,x=-3/2

Find the zeros of 6x(x-1)=21-x

The zeros of 6x(x-1)=21-x are x= 7/3 ,x=-3/2

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6 x (x - 1) = 21 - x

x = \frac{7}{3}, x = - \frac{3}{2}

Decimal Notation

x = 2.33333 \dots, x = - 1.5

Solution steps

6 x (x - 1) = 21 - x

Expand

6 x (x - 1) : 6 x^{2} - 6 x

6 x^{2} - 6 x = 21 - x

Move

x

to the left side

6 x^{2} - 5 x = 21

Move

21

to the left side

6 x^{2} - 5 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 21 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 21) = 23

x_{1, 2} = \frac{- ( - 5 ) \pm 23}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 23}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 23}{2 \cdot 6}

x = \frac{- ( - 5 ) + 23}{2 \cdot 6} : \frac{7}{3}

x = \frac{- ( - 5 ) - 23}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{3}{2}

\frac{x - 3}{2} - \frac{2 x - x}{3} > 3

∣ 5 a + 7 ∣ = ∣ 6 a - 7 ∣

12 g^{2} - 31 g = 10

lo g_{6} (4) + lo g_{6} (3) - lo g_{6} (2) = x

3 y^{2} - 4 y - 2 = 0

What are the solutions to the equation 6x(x-1)=21-x ?
The solutions to the equation 6x(x-1)=21-x are x= 7/3 ,x=-3/2
Find the zeros of 6x(x-1)=21-x
The zeros of 6x(x-1)=21-x are x= 7/3 ,x=-3/2