What are the solutions to the equation r^2+2r+5=0 ?

The solutions to the equation r^2+2r+5=0 are r=-1+2i,r=-1-2i

Find the zeros of r^2+2r+5=0

The zeros of r^2+2r+5=0 are r=-1+2i,r=-1-2i

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r^{2} + 2 r + 5 = 0

r = - 1 + 2 i, r = - 1 - 2 i

Solution steps

r^{2} + 2 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

r_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, r_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

r = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

r = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

r = - 1 + 2 i, r = - 1 - 2 i

7 x^{2} - 28 = 0

- x^{2} + 3 x - 6 + 9 > 3 x - 6 + 2 x^{2}

- 6 x^{2} + 24 x

∣ x - 11 ∣ = ∣ 2 x + 11 ∣

\frac{2 x - 6}{x + 5} \leq 0

What are the solutions to the equation r^2+2r+5=0 ?
The solutions to the equation r^2+2r+5=0 are r=-1+2i,r=-1-2i
Find the zeros of r^2+2r+5=0
The zeros of r^2+2r+5=0 are r=-1+2i,r=-1-2i