What are the solutions to the equation 16=-16t^2+30t+4 ?

The solutions to the equation 16=-16t^2+30t+4 are t=(15-sqrt(33))/(16),t=(15+sqrt(33))/(16)

Find the zeros of 16=-16t^2+30t+4

The zeros of 16=-16t^2+30t+4 are t=(15-sqrt(33))/(16),t=(15+sqrt(33))/(16)

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16 = - 16 t^{2} + 30 t + 4

t = \frac{15 - 33}{16}, t = \frac{15 + 33}{16}

Decimal Notation

t = 0.57846 \dots, t = 1.29653 \dots

Solution steps

16 = - 16 t^{2} + 30 t + 4

Switch sides

- 16 t^{2} + 30 t + 4 = 16

Move

16

to the left side

- 16 t^{2} + 30 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 16 ) ( - 12 )}{2 ( - 16 )}

3 0^{2} - 4 (- 16) (- 12) = 233

t_{1, 2} = \frac{- 30 \pm 2 33}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 30 + 2 33}{2 ( - 16 )}, t_{2} = \frac{- 30 - 2 33}{2 ( - 16 )}

t = \frac{- 30 + 2 33}{2 ( - 16 )} : \frac{15 - 33}{16}

t = \frac{- 30 - 2 33}{2 ( - 16 )} : \frac{15 + 33}{16}

The solutions to the quadratic equation are:

t = \frac{15 - 33}{16}, t = \frac{15 + 33}{16}

(7 t^{- 3})^{3} (s^{5} t^{\frac{1}{4}})^{2}

38

6 x^{2} + 47 x + 35

b^{2} + 2 b + 4 = 0

1 + 4 x^{4} + 4 x^{2}

What are the solutions to the equation 16=-16t^2+30t+4 ?
The solutions to the equation 16=-16t^2+30t+4 are t=(15-sqrt(33))/(16),t=(15+sqrt(33))/(16)
Find the zeros of 16=-16t^2+30t+4
The zeros of 16=-16t^2+30t+4 are t=(15-sqrt(33))/(16),t=(15+sqrt(33))/(16)