-5c>2

Solution

- 5 c > 2

c < - \frac{2}{5}

Interval Notation

(- \infty, - \frac{2}{5})

Decimal Notation

c < - 0.4

Solution steps

- 5 c > 2

Multiply both sides by

- 1

5 c < - 2

Divide both sides by

5

c < - \frac{2}{5}

\frac{1 0 ^{8}}{1 0 ^{5}}

\frac{1 - \frac{s}{t}}{1 + \frac{s}{t}}

\frac{1}{3} (6 - 3 x) + \frac{1}{4} (x - 1) (x - 2) = \frac{x ^{2}}{4}

2 t^{2} + 13 t + 6

3 x^{2} - 5 x + 3 > 2 x^{2} + x - 4