What are the solutions to the equation -2x^2-4x=6 ?

The solutions to the equation -2x^2-4x=6 are x=-1-sqrt(2)i,x=-1+sqrt(2)i

Find the zeros of -2x^2-4x=6

The zeros of -2x^2-4x=6 are x=-1-sqrt(2)i,x=-1+sqrt(2)i

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- 2 x^{2} - 4 x = 6

x = - 1 - 2 i, x = - 1 + 2 i

Solution steps

- 2 x^{2} - 4 x = 6

Move

6

to the left side

- 2 x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 6 )}{2 ( - 2 )}

Simplify

(- 4)^{2} - 4 (- 2) (- 6) : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 4 2 i}{2 ( - 2 )} : - 1 - 2 i

x = \frac{- ( - 4 ) - 4 2 i}{2 ( - 2 )} : - 1 + 2 i

The solutions to the quadratic equation are:

x = - 1 - 2 i, x = - 1 + 2 i

- 11 x - 40 + 2 x^{2} = 0

3 x + 8 < 2 x + 10

s^{5} + 52 s^{4} + s^{3}

x^{2} - 36 = 0

3 x - 8 = x + 8

What are the solutions to the equation -2x^2-4x=6 ?
The solutions to the equation -2x^2-4x=6 are x=-1-sqrt(2)i,x=-1+sqrt(2)i
Find the zeros of -2x^2-4x=6
The zeros of -2x^2-4x=6 are x=-1-sqrt(2)i,x=-1+sqrt(2)i