What are the solutions to the equation -(x-2)(x-4)=0 ?

The solutions to the equation -(x-2)(x-4)=0 are x=2,x=4

Find the zeros of -(x-2)(x-4)=0

The zeros of -(x-2)(x-4)=0 are x=2,x=4

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- (x - 2) (x - 4) = 0

x = 2, x = 4

Solution steps

- (x - 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = 2, x = 4

5 x + 4 = 0

\frac{40 x ^{6} y ^{3}}{16 x ^{6} y ^{3}}

\frac{( a b ^{5} ) ^{\frac{1}{2}}}{( ab ) ^{\frac{1}{2}}}

π - \frac{5 π}{3}

x^{2} - 3 x - 18 = 0

What are the solutions to the equation -(x-2)(x-4)=0 ?
The solutions to the equation -(x-2)(x-4)=0 are x=2,x=4
Find the zeros of -(x-2)(x-4)=0
The zeros of -(x-2)(x-4)=0 are x=2,x=4