What are the solutions to the equation -5(y+3)^2=-45 ?

The solutions to the equation -5(y+3)^2=-45 are y=0,y=-6

Find the zeros of -5(y+3)^2=-45

The zeros of -5(y+3)^2=-45 are y=0,y=-6

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- 5 (y + 3)^{2} = - 45

y = 0, y = - 6

Solution steps

- 5 (y + 3)^{2} = - 45

Divide both sides by

- 5

(y + 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 3 = 9 : y = 0

Solve

y + 3 = - 9 : y = - 6

The solutions to the quadratic equation are:

y = 0, y = - 6

x yz \cdot \frac{1}{x yz}

i^{- 1}

21 c^{2} + 41 c + 10

3 x + 17 = x

x^{3} \cdot x^{4}

What are the solutions to the equation -5(y+3)^2=-45 ?
The solutions to the equation -5(y+3)^2=-45 are y=0,y=-6
Find the zeros of -5(y+3)^2=-45
The zeros of -5(y+3)^2=-45 are y=0,y=-6