What are the solutions to the equation x^2-18x+81=5 ?

The solutions to the equation x^2-18x+81=5 are x=9+sqrt(5),x=9-sqrt(5)

Find the zeros of x^2-18x+81=5

The zeros of x^2-18x+81=5 are x=9+sqrt(5),x=9-sqrt(5)

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x^{2} - 18 x + 81 = 5

x = 9 + 5, x = 9 - 5

Decimal Notation

x = 11.23606 \dots, x = 6.76393 \dots

Solution steps

x^{2} - 18 x + 81 = 5

Move

5

to the left side

x^{2} - 18 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 76}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 76 = 25

x_{1, 2} = \frac{- ( - 18 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 5}{2 \cdot 1} : 9 + 5

x = \frac{- ( - 18 ) - 2 5}{2 \cdot 1} : 9 - 5

The solutions to the quadratic equation are:

x = 9 + 5, x = 9 - 5

∣ 2 x + 1 ∣ = 9

\frac{( a ^{- 2} b ^{3} ) ^{2}}{( a ^{3} b ^{2} ) ^{3}}

2 (x - 14) - x < 7 (x + 2) + x \leq x + 70

\frac{3}{4} x = 4

\frac{12 x + 65}{( x + 4 ) ^{2}} \geq 5

What are the solutions to the equation x^2-18x+81=5 ?
The solutions to the equation x^2-18x+81=5 are x=9+sqrt(5),x=9-sqrt(5)
Find the zeros of x^2-18x+81=5
The zeros of x^2-18x+81=5 are x=9+sqrt(5),x=9-sqrt(5)