What are the solutions to the equation -2x^2-6x=-3 ?

The solutions to the equation -2x^2-6x=-3 are x=-(3+sqrt(15))/2 ,x=(sqrt(15)-3)/2

Find the zeros of -2x^2-6x=-3

The zeros of -2x^2-6x=-3 are x=-(3+sqrt(15))/2 ,x=(sqrt(15)-3)/2

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- 2 x^{2} - 6 x = - 3

x = - \frac{3 + 15}{2}, x = \frac{15 - 3}{2}

Decimal Notation

x = - 3.43649 \dots, x = 0.43649 \dots

Solution steps

- 2 x^{2} - 6 x = - 3

Move

3

to the left side

- 2 x^{2} - 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) \cdot 3 = 215

x_{1, 2} = \frac{- ( - 6 ) \pm 2 15}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 15}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 2 15}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 2 15}{2 ( - 2 )} : - \frac{3 + 15}{2}

x = \frac{- ( - 6 ) - 2 15}{2 ( - 2 )} : \frac{15 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 15}{2}, x = \frac{15 - 3}{2}

36 s^{2} - 4 t^{2}

2 x - 2 = 8

- 2 (x - 8)^{2} > 24

2 x - 4 - (x + 2) = 6 x

5 m^{2} - 3 m = 7

What are the solutions to the equation -2x^2-6x=-3 ?
The solutions to the equation -2x^2-6x=-3 are x=-(3+sqrt(15))/2 ,x=(sqrt(15)-3)/2
Find the zeros of -2x^2-6x=-3
The zeros of -2x^2-6x=-3 are x=-(3+sqrt(15))/2 ,x=(sqrt(15)-3)/2