What are the solutions to the equation 14000=-0.1x^2+90x ?

The solutions to the equation 14000=-0.1x^2+90x are x=200,x=700

Find the zeros of 14000=-0.1x^2+90x

The zeros of 14000=-0.1x^2+90x are x=200,x=700

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14000 = - 0.1 x^{2} + 90 x

x = 200, x = 700

Solution steps

14000 = - 0.1 x^{2} + 90 x

Multiply both sides by

10

140000 = - x^{2} + 900 x

Switch sides

- x^{2} + 900 x = 140000

Move

140000

to the left side

- x^{2} + 900 x - 140000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 900 \pm 90 0 ^{2} - 4 ( - 1 ) ( - 140000 )}{2 ( - 1 )}

90 0^{2} - 4 (- 1) (- 140000) = 500

x_{1, 2} = \frac{- 900 \pm 500}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 900 + 500}{2 ( - 1 )}, x_{2} = \frac{- 900 - 500}{2 ( - 1 )}

x = \frac{- 900 + 500}{2 ( - 1 )} : 200

x = \frac{- 900 - 500}{2 ( - 1 )} : 700

The solutions to the quadratic equation are:

x = 200, x = 700

62 \geq 100

7 \cdot 9

ln (x - 2) < 0

d = (1 - 0)^{2} + (1 - 0)^{2}

\frac{1}{10} - \frac{1}{5}

What are the solutions to the equation 14000=-0.1x^2+90x ?
The solutions to the equation 14000=-0.1x^2+90x are x=200,x=700
Find the zeros of 14000=-0.1x^2+90x
The zeros of 14000=-0.1x^2+90x are x=200,x=700