What are the solutions to the equation y^2+y-6=0 ?

The solutions to the equation y^2+y-6=0 are y=2,y=-3

Find the zeros of y^2+y-6=0

The zeros of y^2+y-6=0 are y=2,y=-3

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y^{2} + y - 6 = 0

y = 2, y = - 3

Solution steps

y^{2} + y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

y_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 1 + 5}{2 \cdot 1}, y_{2} = \frac{- 1 - 5}{2 \cdot 1}

y = \frac{- 1 + 5}{2 \cdot 1} : 2

y = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

y = 2, y = - 3

25 a^{2} - 256

20 x^{2} - 17 x - 10

(7^{6})^{2}

(4 y^{2} + 9 y - 1) - (2 y^{2} + 10)

3 x + 8 = 0

What are the solutions to the equation y^2+y-6=0 ?
The solutions to the equation y^2+y-6=0 are y=2,y=-3
Find the zeros of y^2+y-6=0
The zeros of y^2+y-6=0 are y=2,y=-3