What are the solutions to the equation -2x^2+7x+6=0 ?

The solutions to the equation -2x^2+7x+6=0 are x=-(-7+sqrt(97))/4 ,x=(7+sqrt(97))/4

Find the zeros of -2x^2+7x+6=0

The zeros of -2x^2+7x+6=0 are x=-(-7+sqrt(97))/4 ,x=(7+sqrt(97))/4

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- 2 x^{2} + 7 x + 6 = 0

x = - \frac{- 7 + 97}{4}, x = \frac{7 + 97}{4}

Solution steps

- 2 x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

7^{2} - 4 (- 2) \cdot 6 = 97

x_{1, 2} = \frac{- 7 \pm 97}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 97}{2 ( - 2 )}, x_{2} = \frac{- 7 - 97}{2 ( - 2 )}

x = \frac{- 7 + 97}{2 ( - 2 )} : - \frac{- 7 + 97}{4}

x = \frac{- 7 - 97}{2 ( - 2 )} : \frac{7 + 97}{4}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 97}{4}, x = \frac{7 + 97}{4}

7 (x + 3) \leq 4 x - 5

7 - 4 x = x - 3

f = (- 1)^{2} + 3

\frac{3}{2} - \frac{5}{15}

1 - 2 (3 x - 4) (x - 8) = (9 - 2 x) (8 + 3 x)

What are the solutions to the equation -2x^2+7x+6=0 ?
The solutions to the equation -2x^2+7x+6=0 are x=-(-7+sqrt(97))/4 ,x=(7+sqrt(97))/4
Find the zeros of -2x^2+7x+6=0
The zeros of -2x^2+7x+6=0 are x=-(-7+sqrt(97))/4 ,x=(7+sqrt(97))/4