What is the answer to 1-2(3x-4)(x-8)=(9-2x)(8+3x) ?

The answer to 1-2(3x-4)(x-8)=(9-2x)(8+3x) is x=3

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1-2(3x-4)(x-8)=(9-2x)(8+3x)

1 - 2 (3 x - 4) (x - 8) = (9 - 2 x) (8 + 3 x)

x = 3

Solution steps

1 - 2 (3 x - 4) (x - 8) = (9 - 2 x) (8 + 3 x)

Expand

1 - 2 (3 x - 4) (x - 8) : - 6 x^{2} + 56 x - 63

Expand

(9 - 2 x) (8 + 3 x) : 72 + 11 x - 6 x^{2}

- 6 x^{2} + 56 x - 63 = 72 + 11 x - 6 x^{2}

Move

63

to the right side

- 6 x^{2} + 56 x = - 6 x^{2} + 11 x + 135

Subtract

- 6 x^{2} + 11 x

from both sides

- 6 x^{2} + 56 x - (- 6 x^{2} + 11 x) = - 6 x^{2} + 11 x + 135 - (- 6 x^{2} + 11 x)

Simplify

45 x = 135

Divide both sides by

45

x = 3

(2)^{2}

3^{4} \cdot 2^{- 2} \cdot 4^{2}

a^{3} - 3 a^{2} - 2 a + 6

4 x^{2} + 7 x + 1 = 3

- 48 x^{2} - 6 = 0

What is the answer to 1-2(3x-4)(x-8)=(9-2x)(8+3x) ?
The answer to 1-2(3x-4)(x-8)=(9-2x)(8+3x) is x=3
Solve for x: 1-2(3x-4)(x-8)=(9-2x)(8+3x)
The solution is x=3