What are the solutions to the equation -48x^2-6=0 ?

The solutions to the equation -48x^2-6=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i

Find the zeros of -48x^2-6=0

The zeros of -48x^2-6=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i

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- 48 x^{2} - 6 = 0

x = \frac{1}{2 2} i, x = - \frac{1}{2 2} i

Solution steps

- 48 x^{2} - 6 = 0

Move

6

to the right side

- 48 x^{2} = 6

Divide both sides by

- 48

x^{2} = - \frac{1}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{8}, x = - - \frac{1}{8}

- \frac{1}{8} = \frac{1}{2 2} i

- - \frac{1}{8} = - \frac{1}{2 2} i

x = \frac{1}{2 2} i, x = - \frac{1}{2 2} i

(x + 5) (4 x - 3) = (x + 3) (2 x + 10)

x^{2} + 9 x + 7 = 0

4 y^{2} = 196

- - 40

∣ 4 x - 3 ∣ = 17

What are the solutions to the equation -48x^2-6=0 ?
The solutions to the equation -48x^2-6=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i
Find the zeros of -48x^2-6=0
The zeros of -48x^2-6=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i