What are the solutions to the equation (x+5)(4x-3)=(x+3)(2x+10) ?

The solutions to the equation (x+5)(4x-3)=(x+3)(2x+10) are x=-5,x= 9/2

Find the zeros of (x+5)(4x-3)=(x+3)(2x+10)

The zeros of (x+5)(4x-3)=(x+3)(2x+10) are x=-5,x= 9/2

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(x + 5) (4 x - 3) = (x + 3) (2 x + 10)

x = - 5, x = \frac{9}{2}

Decimal Notation

x = - 5, x = 4.5

Solution steps

(x + 5) (4 x - 3) = (x + 3) (2 x + 10)

Move

(x + 3) (2 x + 10)

to the left side

(x + 5) (4 x - 3) - (x + 3) (2 x + 10) = 0

Factor

(x + 5) (4 x - 3) - (x + 3) (2 x + 10) : (x + 5) (2 x - 9)

(x + 5) (2 x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or 2 x - 9 = 0

Solve

x + 5 = 0 : x = - 5

Solve

2 x - 9 = 0 : x = \frac{9}{2}

The solutions to the quadratic equation are:

x = - 5, x = \frac{9}{2}

x^{2} + 9 x + 7 = 0

4 y^{2} = 196

- - 40

∣ 4 x - 3 ∣ = 17

4 c = 64

What are the solutions to the equation (x+5)(4x-3)=(x+3)(2x+10) ?
The solutions to the equation (x+5)(4x-3)=(x+3)(2x+10) are x=-5,x= 9/2
Find the zeros of (x+5)(4x-3)=(x+3)(2x+10)
The zeros of (x+5)(4x-3)=(x+3)(2x+10) are x=-5,x= 9/2