What are the solutions to the equation 3x^2+8x=3 ?

The solutions to the equation 3x^2+8x=3 are x= 1/3 ,x=-3

Find the zeros of 3x^2+8x=3

The zeros of 3x^2+8x=3 are x= 1/3 ,x=-3

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3 x^{2} + 8 x = 3

x = \frac{1}{3}, x = - 3

Decimal Notation

x = 0.33333 \dots, x = - 3

Solution steps

3 x^{2} + 8 x = 3

Move

3

to the left side

3 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 3) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 3}, x_{2} = \frac{- 8 - 10}{2 \cdot 3}

x = \frac{- 8 + 10}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 8 - 10}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 3

- 3 x = - 1

2 \leq 3 - x \leq 5

2 (3 x + 1) + 2 = 6 x + 4

(l^{2})^{\frac{3}{2}}

x^{2} - 2 = 9 x

What are the solutions to the equation 3x^2+8x=3 ?
The solutions to the equation 3x^2+8x=3 are x= 1/3 ,x=-3
Find the zeros of 3x^2+8x=3
The zeros of 3x^2+8x=3 are x= 1/3 ,x=-3