What are the solutions to the equation x^2-2=9x ?

The solutions to the equation x^2-2=9x are x=(9+sqrt(89))/2 ,x=(9-sqrt(89))/2

Find the zeros of x^2-2=9x

The zeros of x^2-2=9x are x=(9+sqrt(89))/2 ,x=(9-sqrt(89))/2

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x^{2} - 2 = 9 x

x = \frac{9 + 89}{2}, x = \frac{9 - 89}{2}

Solution steps

x^{2} - 2 = 9 x

Move

9 x

to the left side

x^{2} - 2 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 2) = 89

x_{1, 2} = \frac{- ( - 9 ) \pm 89}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 89}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 89}{2 \cdot 1}

x = \frac{- ( - 9 ) + 89}{2 \cdot 1} : \frac{9 + 89}{2}

x = \frac{- ( - 9 ) - 89}{2 \cdot 1} : \frac{9 - 89}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 89}{2}, x = \frac{9 - 89}{2}

c^{2} + 10 c + 24 = 0

14 m^{7} + 10 m^{5} + 16 m^{2}

(X^{5} Y^{4} Z^{3})^{- \frac{2}{3}}

35 x^{2} + 120 x = - 45

64 - 9

What are the solutions to the equation x^2-2=9x ?
The solutions to the equation x^2-2=9x are x=(9+sqrt(89))/2 ,x=(9-sqrt(89))/2
Find the zeros of x^2-2=9x
The zeros of x^2-2=9x are x=(9+sqrt(89))/2 ,x=(9-sqrt(89))/2