What are the solutions to the equation c^2+10c+24=0 ?

The solutions to the equation c^2+10c+24=0 are c=-4,c=-6

Find the zeros of c^2+10c+24=0

The zeros of c^2+10c+24=0 are c=-4,c=-6

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c^{2} + 10 c + 24 = 0

c = - 4, c = - 6

Solution steps

c^{2} + 10 c + 24 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

c_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 10 + 2}{2 \cdot 1}, c_{2} = \frac{- 10 - 2}{2 \cdot 1}

c = \frac{- 10 + 2}{2 \cdot 1} : - 4

c = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

c = - 4, c = - 6

14 m^{7} + 10 m^{5} + 16 m^{2}

(X^{5} Y^{4} Z^{3})^{- \frac{2}{3}}

35 x^{2} + 120 x = - 45

64 - 9

- 14 x + 23 = 14 x - 23

What are the solutions to the equation c^2+10c+24=0 ?
The solutions to the equation c^2+10c+24=0 are c=-4,c=-6
Find the zeros of c^2+10c+24=0
The zeros of c^2+10c+24=0 are c=-4,c=-6