What are the solutions to the equation 0=x^2-8x+7 ?

The solutions to the equation 0=x^2-8x+7 are x=7,x=1

Find the zeros of 0=x^2-8x+7

The zeros of 0=x^2-8x+7 are x=7,x=1

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0 = x^{2} - 8 x + 7

x = 7, x = 1

Solution steps

0 = x^{2} - 8 x + 7

Switch sides

x^{2} - 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- ( - 8 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 6}{2 \cdot 1}

x = \frac{- ( - 8 ) + 6}{2 \cdot 1} : 7

x = \frac{- ( - 8 ) - 6}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 7, x = 1

x - \frac{( 2 - x )}{5} \geq 1 - 2 x

40 x + 5

4 b - 5 = 71

3 x^{4} + 11 x^{3} - 22 x^{2} - 30 x + 12

15 x^{2} + 3 x - 9 = 0

What are the solutions to the equation 0=x^2-8x+7 ?
The solutions to the equation 0=x^2-8x+7 are x=7,x=1
Find the zeros of 0=x^2-8x+7
The zeros of 0=x^2-8x+7 are x=7,x=1