What are the solutions to the equation 15x^2+3x-9=0 ?

The solutions to the equation 15x^2+3x-9=0 are x=(-1+sqrt(61))/(10),x=-(1+sqrt(61))/(10)

Find the zeros of 15x^2+3x-9=0

The zeros of 15x^2+3x-9=0 are x=(-1+sqrt(61))/(10),x=-(1+sqrt(61))/(10)

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15 x^{2} + 3 x - 9 = 0

x = \frac{- 1 + 61}{10}, x = - \frac{1 + 61}{10}

Solution steps

15 x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 15 ( - 9 )}{2 \cdot 15}

3^{2} - 4 \cdot 15 (- 9) = 361

x_{1, 2} = \frac{- 3 \pm 3 61}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 3 + 3 61}{2 \cdot 15}, x_{2} = \frac{- 3 - 3 61}{2 \cdot 15}

x = \frac{- 3 + 3 61}{2 \cdot 15} : \frac{- 1 + 61}{10}

x = \frac{- 3 - 3 61}{2 \cdot 15} : - \frac{1 + 61}{10}

The solutions to the quadratic equation are:

x = \frac{- 1 + 61}{10}, x = - \frac{1 + 61}{10}

x^{2} + 20 x - 1500 = 0

27 + x^{3}

3 x^{2} + 7 x - 20

∣ 4 x + 2 ∣ + 6 = 0

3 x^{2} + 24 x + 55 = 7

What are the solutions to the equation 15x^2+3x-9=0 ?
The solutions to the equation 15x^2+3x-9=0 are x=(-1+sqrt(61))/(10),x=-(1+sqrt(61))/(10)
Find the zeros of 15x^2+3x-9=0
The zeros of 15x^2+3x-9=0 are x=(-1+sqrt(61))/(10),x=-(1+sqrt(61))/(10)