What are the solutions to the equation x^2+20x-1500=0 ?

The solutions to the equation x^2+20x-1500=0 are x=30,x=-50

Find the zeros of x^2+20x-1500=0

The zeros of x^2+20x-1500=0 are x=30,x=-50

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 20 x - 1500 = 0

x = 30, x = - 50

Solution steps

x^{2} + 20 x - 1500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 1500 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 1500) = 80

x_{1, 2} = \frac{- 20 \pm 80}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 80}{2 \cdot 1}, x_{2} = \frac{- 20 - 80}{2 \cdot 1}

x = \frac{- 20 + 80}{2 \cdot 1} : 30

x = \frac{- 20 - 80}{2 \cdot 1} : - 50

The solutions to the quadratic equation are:

x = 30, x = - 50

27 + x^{3}

3 x^{2} + 7 x - 20

∣ 4 x + 2 ∣ + 6 = 0

3 x^{2} + 24 x + 55 = 7

3 (x - 10) = - 9

What are the solutions to the equation x^2+20x-1500=0 ?
The solutions to the equation x^2+20x-1500=0 are x=30,x=-50
Find the zeros of x^2+20x-1500=0
The zeros of x^2+20x-1500=0 are x=30,x=-50