What are the solutions to the equation 2x^2-3x=14 ?

The solutions to the equation 2x^2-3x=14 are x= 7/2 ,x=-2

Find the zeros of 2x^2-3x=14

The zeros of 2x^2-3x=14 are x= 7/2 ,x=-2

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2 x^{2} - 3 x = 14

x = \frac{7}{2}, x = - 2

Decimal Notation

x = 3.5, x = - 2

Solution steps

2 x^{2} - 3 x = 14

Move

14

to the left side

2 x^{2} - 3 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 14) = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 2}

x = \frac{- ( - 3 ) + 11}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 3 ) - 11}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 2

s + 1 \leq 3

(\frac{1}{9})^{\frac{- 1}{2}}

- x^{2} + 18 = 93

\frac{5}{6} - \frac{4}{8}

2 x^{2} - 8 x + 5 = 0

What are the solutions to the equation 2x^2-3x=14 ?
The solutions to the equation 2x^2-3x=14 are x= 7/2 ,x=-2
Find the zeros of 2x^2-3x=14
The zeros of 2x^2-3x=14 are x= 7/2 ,x=-2