What are the solutions to the equation s^2+8s-125=0 ?

The solutions to the equation s^2+8s-125=0 are s=-4+sqrt(141),s=-4-sqrt(141)

Find the zeros of s^2+8s-125=0

The zeros of s^2+8s-125=0 are s=-4+sqrt(141),s=-4-sqrt(141)

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s^{2} + 8 s - 125 = 0

s = - 4 + 141, s = - 4 - 141

Solution steps

s^{2} + 8 s - 125 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 125 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 125) = 2141

s_{1, 2} = \frac{- 8 \pm 2 141}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 2 141}{2 \cdot 1}, s_{2} = \frac{- 8 - 2 141}{2 \cdot 1}

s = \frac{- 8 + 2 141}{2 \cdot 1} : - 4 + 141

s = \frac{- 8 - 2 141}{2 \cdot 1} : - 4 - 141

The solutions to the quadratic equation are:

s = - 4 + 141, s = - 4 - 141

x^{2} + 10 x + 5 = 0

(3 x + 5)^{2} - 39 = - 22

3 m^{- 4}

\frac{3}{5} (x - 6) = \frac{2}{3} (3 x - 5)

\frac{( ( x + y ) ( e x yy ) - e x y ( 1 ) )}{( x + y ) ^{2}}

What are the solutions to the equation s^2+8s-125=0 ?
The solutions to the equation s^2+8s-125=0 are s=-4+sqrt(141),s=-4-sqrt(141)
Find the zeros of s^2+8s-125=0
The zeros of s^2+8s-125=0 are s=-4+sqrt(141),s=-4-sqrt(141)