What is (i^5-i^{-8})/(sqrt(2)i) ?

The solution to (i^5-i^{-8})/(sqrt(2)i) is 1/(sqrt(2))+1/(sqrt(2))i

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simplify (i^5-i^{-8})/(sqrt(2)i)

simplify

\frac{i ^{5} - i ^{- 8}}{2 i}

\frac{1}{2} + \frac{1}{2} i

Solution steps

\frac{i ^{5} - i ^{- 8}}{2 i}

Multiply by the conjugate

\frac{- i}{- i}

= \frac{( i ^{5} - i ^{- 8} ) ( - i )}{2 i ( - i )}

Simplify

\frac{( i ^{5} - i ^{- 8} ) ( - i )}{2 i ( - i )} : \frac{1 + i}{2}

= \frac{1 + i}{2}

Rewrite in standard complex form:

\frac{1}{2} + \frac{1}{2} i

= \frac{1}{2} + \frac{1}{2} i

- (x - 1)^{5} (x + 1)^{3} \leq 0

\frac{y}{8} + 19 = 30

- 5 (- x - 4) - 3 x - 5 = 13

3 x + 2 = 2 + 3 x

- - 48

What is (i^5-i^{-8})/(sqrt(2)i) ?
The solution to (i^5-i^{-8})/(sqrt(2)i) is 1/(sqrt(2))+1/(sqrt(2))i