What are the solutions to the equation 3x^2-3x-4=0 ?

The solutions to the equation 3x^2-3x-4=0 are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6

Find the zeros of 3x^2-3x-4=0

The zeros of 3x^2-3x-4=0 are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6

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3 x^{2} - 3 x - 4 = 0

x = \frac{3 + 57}{6}, x = \frac{3 - 57}{6}

Solution steps

3 x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 4) = 57

x_{1, 2} = \frac{- ( - 3 ) \pm 57}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 57}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 57}{2 \cdot 3}

x = \frac{- ( - 3 ) + 57}{2 \cdot 3} : \frac{3 + 57}{6}

x = \frac{- ( - 3 ) - 57}{2 \cdot 3} : \frac{3 - 57}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 57}{6}, x = \frac{3 - 57}{6}

\frac{1}{x} < 5

6 q^{2} - 5 pq - 6 q + 5 p

0 = 3 x^{2} + x - 2

x (9 x - 2) = 11

8 \cdot 10

What are the solutions to the equation 3x^2-3x-4=0 ?
The solutions to the equation 3x^2-3x-4=0 are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6
Find the zeros of 3x^2-3x-4=0
The zeros of 3x^2-3x-4=0 are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6