What are the solutions to the equation 0=3x^2+x-2 ?

The solutions to the equation 0=3x^2+x-2 are x= 2/3 ,x=-1

Find the zeros of 0=3x^2+x-2

The zeros of 0=3x^2+x-2 are x= 2/3 ,x=-1

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0 = 3 x^{2} + x - 2

x = \frac{2}{3}, x = - 1

Solution steps

0 = 3 x^{2} + x - 2

Switch sides

3 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 3}, x_{2} = \frac{- 1 - 5}{2 \cdot 3}

x = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

x (9 x - 2) = 11

8 \cdot 10

4 (6 + x) = 48

\frac{x}{1} = 2

496.4 = 200 + 4 x + 0.1 x^{2}

What are the solutions to the equation 0=3x^2+x-2 ?
The solutions to the equation 0=3x^2+x-2 are x= 2/3 ,x=-1
Find the zeros of 0=3x^2+x-2
The zeros of 0=3x^2+x-2 are x= 2/3 ,x=-1