What are the solutions to the equation -4x^2+10=0 ?

The solutions to the equation -4x^2+10=0 are x=sqrt(5/2),x=-sqrt(5/2)

Find the zeros of -4x^2+10=0

The zeros of -4x^2+10=0 are x=sqrt(5/2),x=-sqrt(5/2)

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- 4 x^{2} + 10 = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.58113 \dots, x = - 1.58113 \dots

Solution steps

- 4 x^{2} + 10 = 0

Move

10

to the right side

- 4 x^{2} = - 10

Divide both sides by

- 4

x^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2}, x = - \frac{5}{2}

4 x^{2} - 9 x - 28 = 0

(15 - 3)^{2}

2 p + 2 < 6

169 = 275 - u

∣ 4 + 2 x ∣ = ∣ 5 - x ∣

What are the solutions to the equation -4x^2+10=0 ?
The solutions to the equation -4x^2+10=0 are x=sqrt(5/2),x=-sqrt(5/2)
Find the zeros of -4x^2+10=0
The zeros of -4x^2+10=0 are x=sqrt(5/2),x=-sqrt(5/2)