What are the solutions to the equation 6w^2+19w-15=-4w^2 ?

The solutions to the equation 6w^2+19w-15=-4w^2 are w= 3/5 ,w=-5/2

Find the zeros of 6w^2+19w-15=-4w^2

The zeros of 6w^2+19w-15=-4w^2 are w= 3/5 ,w=-5/2

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6 w^{2} + 19 w - 15 = - 4 w^{2}

w = \frac{3}{5}, w = - \frac{5}{2}

Solution steps

6 w^{2} + 19 w - 15 = - 4 w^{2}

Move

4 w^{2}

to the left side

10 w^{2} + 19 w - 15 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 10 ( - 15 )}{2 \cdot 10}

1 9^{2} - 4 \cdot 10 (- 15) = 31

w_{1, 2} = \frac{- 19 \pm 31}{2 \cdot 10}

Separate the solutions

w_{1} = \frac{- 19 + 31}{2 \cdot 10}, w_{2} = \frac{- 19 - 31}{2 \cdot 10}

w = \frac{- 19 + 31}{2 \cdot 10} : \frac{3}{5}

w = \frac{- 19 - 31}{2 \cdot 10} : - \frac{5}{2}

The solutions to the quadratic equation are:

w = \frac{3}{5}, w = - \frac{5}{2}

\frac{1}{4} (1)

9 n^{2} + 79 = - 18 n

- 0.000024 x^{2} - 0.02 x + 150 = 0

2 - x - x^{2}

x + 8 = x + 8^{2} + 7 (x + 8) + 4

What are the solutions to the equation 6w^2+19w-15=-4w^2 ?
The solutions to the equation 6w^2+19w-15=-4w^2 are w= 3/5 ,w=-5/2
Find the zeros of 6w^2+19w-15=-4w^2
The zeros of 6w^2+19w-15=-4w^2 are w= 3/5 ,w=-5/2