What are the solutions to the equation 9n^2+79=-18n ?

The solutions to the equation 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3

Find the zeros of 9n^2+79=-18n

The zeros of 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3

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9 n^{2} + 79 = - 18 n

n = - 1 + i \frac{70}{3}, n = - 1 - i \frac{70}{3}

Solution steps

9 n^{2} + 79 = - 18 n

Move

18 n

to the left side

9 n^{2} + 79 + 18 n = 0

Write in the standard form

a x^{2} + b x + c = 0

9 n^{2} + 18 n + 79 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 79}{2 \cdot 9}

Simplify

1 8^{2} - 4 \cdot 9 \cdot 79 : 670 i

n_{1, 2} = \frac{- 18 \pm 6 70 i}{2 \cdot 9}

Separate the solutions

n_{1} = \frac{- 18 + 6 70 i}{2 \cdot 9}, n_{2} = \frac{- 18 - 6 70 i}{2 \cdot 9}

n = \frac{- 18 + 6 70 i}{2 \cdot 9} : - 1 + i \frac{70}{3}

n = \frac{- 18 - 6 70 i}{2 \cdot 9} : - 1 - i \frac{70}{3}

The solutions to the quadratic equation are:

n = - 1 + i \frac{70}{3}, n = - 1 - i \frac{70}{3}

- 0.000024 x^{2} - 0.02 x + 150 = 0

2 - x - x^{2}

x + 8 = x + 8^{2} + 7 (x + 8) + 4

- 4 x^{2} + 16 = 0

- 4 < 2 - 3 (x + 2) < 11

What are the solutions to the equation 9n^2+79=-18n ?
The solutions to the equation 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3
Find the zeros of 9n^2+79=-18n
The zeros of 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3