What are the solutions to the equation -4x^2+16=0 ?

The solutions to the equation -4x^2+16=0 are x=2,x=-2

Find the zeros of -4x^2+16=0

The zeros of -4x^2+16=0 are x=2,x=-2

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- 4 x^{2} + 16 = 0

x = 2, x = - 2

Solution steps

- 4 x^{2} + 16 = 0

Move

16

to the right side

- 4 x^{2} = - 16

Divide both sides by

- 4

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

- 4 < 2 - 3 (x + 2) < 11

4 x = 30

2 + 5 (3 b + 9) - b

x^{2} + 17 x + 42 = 0

0.0625

What are the solutions to the equation -4x^2+16=0 ?
The solutions to the equation -4x^2+16=0 are x=2,x=-2
Find the zeros of -4x^2+16=0
The zeros of -4x^2+16=0 are x=2,x=-2