What are the solutions to the equation (2x-3)^2-72=0 ?

The solutions to the equation (2x-3)^2-72=0 are x=(6sqrt(2)+3)/2 ,x=(-6sqrt(2)+3)/2

Find the zeros of (2x-3)^2-72=0

The zeros of (2x-3)^2-72=0 are x=(6sqrt(2)+3)/2 ,x=(-6sqrt(2)+3)/2

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(2 x - 3)^{2} - 72 = 0

x = \frac{6 2 + 3}{2}, x = \frac{- 6 2 + 3}{2}

Solution steps

(2 x - 3)^{2} - 72 = 0

Move

72

to the right side

(2 x - 3)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 72 : x = \frac{6 2 + 3}{2}

Solve

2 x - 3 = - 72 : x = \frac{- 6 2 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{6 2 + 3}{2}, x = \frac{- 6 2 + 3}{2}

x^{2} + 16 x y + 63 y^{2}

q^{2} = - 81

4 x^{2} + 35 x + 24 = 0

5 - 8 x < 2 x + 3

(7 x)^{3}

What are the solutions to the equation (2x-3)^2-72=0 ?
The solutions to the equation (2x-3)^2-72=0 are x=(6sqrt(2)+3)/2 ,x=(-6sqrt(2)+3)/2
Find the zeros of (2x-3)^2-72=0
The zeros of (2x-3)^2-72=0 are x=(6sqrt(2)+3)/2 ,x=(-6sqrt(2)+3)/2