What are the solutions to the equation 2x^2=1 ?

The solutions to the equation 2x^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 2x^2=1

The zeros of 2x^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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2 x^{2} = 1

x = \frac{1}{2}, x = - \frac{1}{2}

Solution steps

2 x^{2} = 1

Divide both sides by

2

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{r + 6}{5} = \frac{r + 8}{7}

k^{2} - 5 k = k + 7

6 x^{2} y - 28 x y + 30 y

14 = x 2

\frac{- 4 w ^{- 4} x ^{3}}{12 w ^{5} x ^{- \frac{1}{8}}}

What are the solutions to the equation 2x^2=1 ?
The solutions to the equation 2x^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 2x^2=1
The zeros of 2x^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))