What is factor 4x^2-x-5 ?

The solution to factor 4x^2-x-5 is (x+1)(4x-5)

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factor 4x^2-x-5

factor

4 x^{2} - x - 5

(x + 1) (4 x - 5)

Solution steps

4 x^{2} - x - 5

Break the expression into groups

= (4 x^{2} + 4 x) + (- 5 x - 5)

Factor out

4 x

from

4 x^{2} + 4 x : 4 x (x + 1)

Factor out

- 5

from

- 5 x - 5 : - 5 (x + 1)

= 4 x (x + 1) - 5 (x + 1)

Factor out common term

x + 1

= (x + 1) (4 x - 5)

\frac{1}{14} + \frac{51}{70}

1 = - 8 + 3 x

\frac{m ^{2} - 4 m + 4}{m ^{2} + m - 6}

\frac{8 m + 6}{2} + 6 = \frac{10 m + 5}{7}

- 2 x^{2} + 6 x + 7 = 0