What is (m^2-4m+4)/(m^2+m-6) ?

The solution to (m^2-4m+4)/(m^2+m-6) is (m-2)/(m+3)

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simplify (m^2-4m+4)/(m^2+m-6)

simplify

\frac{m ^{2} - 4 m + 4}{m ^{2} + m - 6}

\frac{m - 2}{m + 3}

Solution steps

\frac{m ^{2} - 4 m + 4}{m ^{2} + m - 6}

Factor

m^{2} - 4 m + 4 : (m - 2)^{2}

= \frac{( m - 2 ) ^{2}}{m ^{2} + m - 6}

Factor

m^{2} + m - 6 : (m - 2) (m + 3)

= \frac{( m - 2 ) ^{2}}{( m - 2 ) ( m + 3 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(m - 2)^{2} = (m - 2) (m - 2)

= \frac{( m - 2 ) ( m - 2 )}{( m - 2 ) ( m + 3 )}

Cancel the common factor:

m - 2

= \frac{m - 2}{m + 3}

\frac{8 m + 6}{2} + 6 = \frac{10 m + 5}{7}

- 2 x^{2} + 6 x + 7 = 0

4 x^{2} + 14 x + 12

5 (2 x + 2) = 20

(7 + 8 m) - 5 \geq - 11

What is (m^2-4m+4)/(m^2+m-6) ?
The solution to (m^2-4m+4)/(m^2+m-6) is (m-2)/(m+3)