What are the solutions to the equation -2x^2+6x+7=0 ?

The solutions to the equation -2x^2+6x+7=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2

Find the zeros of -2x^2+6x+7=0

The zeros of -2x^2+6x+7=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2

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- 2 x^{2} + 6 x + 7 = 0

x = - \frac{- 3 + 23}{2}, x = \frac{3 + 23}{2}

Decimal Notation

x = - 0.89791 \dots, x = 3.89791 \dots

Solution steps

- 2 x^{2} + 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

6^{2} - 4 (- 2) \cdot 7 = 223

x_{1, 2} = \frac{- 6 \pm 2 23}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 23}{2 ( - 2 )}, x_{2} = \frac{- 6 - 2 23}{2 ( - 2 )}

x = \frac{- 6 + 2 23}{2 ( - 2 )} : - \frac{- 3 + 23}{2}

x = \frac{- 6 - 2 23}{2 ( - 2 )} : \frac{3 + 23}{2}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 23}{2}, x = \frac{3 + 23}{2}

(\frac{1}{4})^{7}

4 x^{2} + 14 x + 12

5 (2 x + 2) = 20

(7 + 8 m) - 5 \geq - 11

2 w^{2} - 9 w + 3 = - 4 w

What are the solutions to the equation -2x^2+6x+7=0 ?
The solutions to the equation -2x^2+6x+7=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2
Find the zeros of -2x^2+6x+7=0
The zeros of -2x^2+6x+7=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2