What are the solutions to the equation 2w^2-9w+3=-4w ?

The solutions to the equation 2w^2-9w+3=-4w are w= 3/2 ,w=1

Find the zeros of 2w^2-9w+3=-4w

The zeros of 2w^2-9w+3=-4w are w= 3/2 ,w=1

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2 w^{2} - 9 w + 3 = - 4 w

w = \frac{3}{2}, w = 1

Decimal Notation

w = 1.5, w = 1

Solution steps

2 w^{2} - 9 w + 3 = - 4 w

Move

4 w

to the left side

2 w^{2} - 5 w + 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 3 = 1

w_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 2}, w_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 2}

w = \frac{- ( - 5 ) + 1}{2 \cdot 2} : \frac{3}{2}

w = \frac{- ( - 5 ) - 1}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

w = \frac{3}{2}, w = 1

- \frac{5 π}{6} + π

3 (16 - 4 y) + 4 y = 8

4 x^{2} + 2 x = 17

5 x + 5 = 3 x + 4

What are the solutions to the equation 2w^2-9w+3=-4w ?
The solutions to the equation 2w^2-9w+3=-4w are w= 3/2 ,w=1
Find the zeros of 2w^2-9w+3=-4w
The zeros of 2w^2-9w+3=-4w are w= 3/2 ,w=1