What are the solutions to the equation 4x^2+2x=17 ?

The solutions to the equation 4x^2+2x=17 are x=(-1+sqrt(69))/4 ,x=-(1+sqrt(69))/4

Find the zeros of 4x^2+2x=17

The zeros of 4x^2+2x=17 are x=(-1+sqrt(69))/4 ,x=-(1+sqrt(69))/4

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4 x^{2} + 2 x = 17

x = \frac{- 1 + 69}{4}, x = - \frac{1 + 69}{4}

Decimal Notation

x = 1.82665 \dots, x = - 2.32665 \dots

Solution steps

4 x^{2} + 2 x = 17

Move

17

to the left side

4 x^{2} + 2 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 17 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 17) = 269

x_{1, 2} = \frac{- 2 \pm 2 69}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 2 69}{2 \cdot 4}, x_{2} = \frac{- 2 - 2 69}{2 \cdot 4}

x = \frac{- 2 + 2 69}{2 \cdot 4} : \frac{- 1 + 69}{4}

x = \frac{- 2 - 2 69}{2 \cdot 4} : - \frac{1 + 69}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 69}{4}, x = - \frac{1 + 69}{4}

5 x + 5 = 3 x + 4

3 x^{2} - 36 x - 18

10 - 9 x^{2} + 4 x = - 6 x^{2}

k^{2} + 5 k - 6 = 0

What are the solutions to the equation 4x^2+2x=17 ?
The solutions to the equation 4x^2+2x=17 are x=(-1+sqrt(69))/4 ,x=-(1+sqrt(69))/4
Find the zeros of 4x^2+2x=17
The zeros of 4x^2+2x=17 are x=(-1+sqrt(69))/4 ,x=-(1+sqrt(69))/4