What are the solutions to the equation 10-9x^2+4x=-6x^2 ?

The solutions to the equation 10-9x^2+4x=-6x^2 are x=-(-2+sqrt(34))/3 ,x=(2+sqrt(34))/3

Find the zeros of 10-9x^2+4x=-6x^2

The zeros of 10-9x^2+4x=-6x^2 are x=-(-2+sqrt(34))/3 ,x=(2+sqrt(34))/3

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10 - 9 x^{2} + 4 x = - 6 x^{2}

x = - \frac{- 2 + 34}{3}, x = \frac{2 + 34}{3}

Decimal Notation

x = - 1.27698 \dots, x = 2.61031 \dots

Solution steps

10 - 9 x^{2} + 4 x = - 6 x^{2}

Move

6 x^{2}

to the left side

- 3 x^{2} + 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 3 ) \cdot 10}{2 ( - 3 )}

4^{2} - 4 (- 3) \cdot 10 = 234

x_{1, 2} = \frac{- 4 \pm 2 34}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 34}{2 ( - 3 )}, x_{2} = \frac{- 4 - 2 34}{2 ( - 3 )}

x = \frac{- 4 + 2 34}{2 ( - 3 )} : - \frac{- 2 + 34}{3}

x = \frac{- 4 - 2 34}{2 ( - 3 )} : \frac{2 + 34}{3}

The solutions to the quadratic equation are:

x = - \frac{- 2 + 34}{3}, x = \frac{2 + 34}{3}

k^{2} + 5 k - 6 = 0

(2 x)^{2} 2 y

d^{2} - 6 d - 7

\frac{1}{2} - x + \frac{3}{2} = x - 4

6 x^{2} - 5 x - 21 = 0

What are the solutions to the equation 10-9x^2+4x=-6x^2 ?
The solutions to the equation 10-9x^2+4x=-6x^2 are x=-(-2+sqrt(34))/3 ,x=(2+sqrt(34))/3
Find the zeros of 10-9x^2+4x=-6x^2
The zeros of 10-9x^2+4x=-6x^2 are x=-(-2+sqrt(34))/3 ,x=(2+sqrt(34))/3