What are the solutions to the equation 50^2+120^2=c^2 ?

The solutions to the equation 50^2+120^2=c^2 are c=130,c=-130

Find the zeros of 50^2+120^2=c^2

The zeros of 50^2+120^2=c^2 are c=130,c=-130

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5 0^{2} + 12 0^{2} = c^{2}

c = 130, c = - 130

Solution steps

5 0^{2} + 12 0^{2} = c^{2}

Switch sides

c^{2} = 5 0^{2} + 12 0^{2}

Simplify

5 0^{2} + 12 0^{2} : 16900

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 16900, c = - 16900

16900 = 130

- 16900 = - 130

c = 130, c = - 130

2 ∣ 2 x - 7 ∣ + 12 > 18

2 x^{2} + 2 x - 234 = \frac{5}{8} x^{2} - x

(2 x - 1)^{2} = 0

5 (x - 3)^{2} - 6 = 74

1 - y = 6

What are the solutions to the equation 50^2+120^2=c^2 ?
The solutions to the equation 50^2+120^2=c^2 are c=130,c=-130
Find the zeros of 50^2+120^2=c^2
The zeros of 50^2+120^2=c^2 are c=130,c=-130