What are the solutions to the equation -4x^2+28x-49=0 ?

The solutions to the equation -4x^2+28x-49=0 are x= 7/2

Find the zeros of -4x^2+28x-49=0

The zeros of -4x^2+28x-49=0 are x= 7/2

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- 4 x^{2} + 28 x - 49 = 0

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

- 4 x^{2} + 28 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 ( - 4 ) ( - 49 )}{2 ( - 4 )}

2 8^{2} - 4 (- 4) (- 49) = 0

x_{1, 2} = \frac{- 28 \pm 0}{2 ( - 4 )}

x = \frac{- 28}{2 ( - 4 )}

\frac{- 28}{2 ( - 4 )} = \frac{7}{2}

x = \frac{7}{2}

The solution to the quadratic equation is:

x = \frac{7}{2}

- 3 \cdot (10 i + 6)

a^{4} b^{2} - a^{2} b

- 5 x^{2} + 9 = 9 x + 13

\frac{r - 4}{r - 1} \geq 0

\frac{2 x + 5}{3} \geq \frac{3 x - 1}{2}

What are the solutions to the equation -4x^2+28x-49=0 ?
The solutions to the equation -4x^2+28x-49=0 are x= 7/2
Find the zeros of -4x^2+28x-49=0
The zeros of -4x^2+28x-49=0 are x= 7/2