What are the solutions to the equation 0=x^2-16x+64 ?

The solutions to the equation 0=x^2-16x+64 are x=8

Find the zeros of 0=x^2-16x+64

The zeros of 0=x^2-16x+64 are x=8

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0 = x^{2} - 16 x + 64

x = 8

Solution steps

0 = x^{2} - 16 x + 64

Switch sides

x^{2} - 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

x = 8

The solution to the quadratic equation is:

x = 8

t^{2} + t + \frac{1}{4}

x^{2} + 14 x + 42 = 0

\frac{19 m + 3 m ^{3}}{14 m - 3} - \frac{12 m ^{2} + 3 m}{14 m - 3}

49 a^{2} - 14 a + 1

∣ x - 2 ∣ - 5 \leq - 2

What are the solutions to the equation 0=x^2-16x+64 ?
The solutions to the equation 0=x^2-16x+64 are x=8
Find the zeros of 0=x^2-16x+64
The zeros of 0=x^2-16x+64 are x=8