What is ((1+7i))/((3-2i)) ?

The solution to ((1+7i))/((3-2i)) is -11/13+23/13 i

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simplify ((1+7i))/((3-2i))

simplify

\frac{( 1 + 7 i )}{( 3 - 2 i )}

- \frac{11}{13} + \frac{23}{13} i

Solution steps

\frac{1 + 7 i}{3 - 2 i}

Multiply by the conjugate

\frac{3 + 2 i}{3 + 2 i}

= \frac{( 1 + 7 i ) ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )}

Simplify

\frac{( 1 + 7 i ) ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )} : \frac{- 11 + 23 i}{13}

= \frac{- 11 + 23 i}{13}

Rewrite in standard complex form:

- \frac{11}{13} + \frac{23}{13} i

= - \frac{11}{13} + \frac{23}{13} i

125 a^{3} - 27 b^{3}

- \frac{5}{7} \cdot \frac{99}{5}

w^{2} - 15 w + 26

- 15 + 8

2 x^{(2)} + 4 x + 1 = 0