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What are the solutions to the equation 2x^{(2)}+4x+1=0 ?
The solutions to the equation 2x^{(2)}+4x+1=0 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))Find the zeros of 2x^{(2)}+4x+1=0
The zeros of 2x^{(2)}+4x+1=0 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))