What are the solutions to the equation x^2-8x=-15 ?

The solutions to the equation x^2-8x=-15 are x=5,x=3

Find the zeros of x^2-8x=-15

The zeros of x^2-8x=-15 are x=5,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 8 x = - 15

x = 5, x = 3

Solution steps

x^{2} - 8 x = - 15

Move

15

to the left side

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

2 w^{2} + 11 w - 63

5 x^{2} - 19 x y + 12 y^{2}

4 (x - 1) > x^{2} + 9

3 x^{2} + 30 x + 50 = 0

3 x^{2} + 6 x + 3 = 0

What are the solutions to the equation x^2-8x=-15 ?
The solutions to the equation x^2-8x=-15 are x=5,x=3
Find the zeros of x^2-8x=-15
The zeros of x^2-8x=-15 are x=5,x=3