What are the solutions to the equation 3x^2+6x+3=0 ?

The solutions to the equation 3x^2+6x+3=0 are x=-1

Find the zeros of 3x^2+6x+3=0

The zeros of 3x^2+6x+3=0 are x=-1

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3 x^{2} + 6 x + 3 = 0

x = - 1

Solution steps

3 x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

x = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

x - 6 = - x^{2}

3 (x + 3) + x = 2 (x - 1) + 3

- 2 x^{2} + 4 x = - 12

\frac{m - 4}{3} - \frac{3 m - 1}{5} = 1

3 - \frac{3 x}{4} = 6

What are the solutions to the equation 3x^2+6x+3=0 ?
The solutions to the equation 3x^2+6x+3=0 are x=-1
Find the zeros of 3x^2+6x+3=0
The zeros of 3x^2+6x+3=0 are x=-1