What are the solutions to the equation -2x^2+4x=-12 ?

The solutions to the equation -2x^2+4x=-12 are x=1-sqrt(7),x=1+sqrt(7)

Find the zeros of -2x^2+4x=-12

The zeros of -2x^2+4x=-12 are x=1-sqrt(7),x=1+sqrt(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 4 x = - 12

x = 1 - 7, x = 1 + 7

Decimal Notation

x = - 1.64575 \dots, x = 3.64575 \dots

Solution steps

- 2 x^{2} + 4 x = - 12

Move

12

to the left side

- 2 x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 12}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 12 = 47

x_{1, 2} = \frac{- 4 \pm 4 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 7}{2 ( - 2 )}, x_{2} = \frac{- 4 - 4 7}{2 ( - 2 )}

x = \frac{- 4 + 4 7}{2 ( - 2 )} : 1 - 7

x = \frac{- 4 - 4 7}{2 ( - 2 )} : 1 + 7

The solutions to the quadratic equation are:

x = 1 - 7, x = 1 + 7

\frac{m - 4}{3} - \frac{3 m - 1}{5} = 1

3 - \frac{3 x}{4} = 6

x^{2} + 6 x = 10

6 x^{2} - 7 x - 3 = 0

\frac{3 x + 5}{2} - \frac{4 x - 5}{3} = \frac{7 x + 1}{6} - 5

What are the solutions to the equation -2x^2+4x=-12 ?
The solutions to the equation -2x^2+4x=-12 are x=1-sqrt(7),x=1+sqrt(7)
Find the zeros of -2x^2+4x=-12
The zeros of -2x^2+4x=-12 are x=1-sqrt(7),x=1+sqrt(7)