What are the solutions to the equation 0=2x^2-7x-30 ?

The solutions to the equation 0=2x^2-7x-30 are x=6,x=-5/2

Find the zeros of 0=2x^2-7x-30

The zeros of 0=2x^2-7x-30 are x=6,x=-5/2

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0 = 2 x^{2} - 7 x - 30

x = 6, x = - \frac{5}{2}

Solution steps

0 = 2 x^{2} - 7 x - 30

Switch sides

2 x^{2} - 7 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 30 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 30) = 17

x_{1, 2} = \frac{- ( - 7 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 17}{2 \cdot 2}

x = \frac{- ( - 7 ) + 17}{2 \cdot 2} : 6

x = \frac{- ( - 7 ) - 17}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 6, x = - \frac{5}{2}

- x^{2} - 5 x - 4 > 0

x^{2} + 18 x + 129 = 0

2 x + 11 = - 2 x - 8

\frac{3}{4} y - 11 \leq \frac{6}{5} + 12 y

1.75 \cdot 1 0^{- 5} = \frac{x ^{2}}{0.1}

What are the solutions to the equation 0=2x^2-7x-30 ?
The solutions to the equation 0=2x^2-7x-30 are x=6,x=-5/2
Find the zeros of 0=2x^2-7x-30
The zeros of 0=2x^2-7x-30 are x=6,x=-5/2