What is 1/(6ab^4)-3/(8a^3b^2) ?

The solution to 1/(6ab^4)-3/(8a^3b^2) is (4a^2-9b^2)/(24a^3b^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/(6ab^4)-3/(8a^3b^2)

simplify

\frac{1}{6 a b ^{4}} - \frac{3}{8 a ^{3} b ^{2}}

\frac{4 a ^{2} - 9 b ^{2}}{24 a ^{3} b ^{4}}

Solution steps

\frac{1}{6 a b ^{4}} - \frac{3}{8 a ^{3} b ^{2}}

Least Common Multiplier of

6 a b^{4}, 8 a^{3} b^{2} : 24 a^{3} b^{4}

Adjust Fractions based on the LCM

= \frac{4 a ^{2}}{24 a ^{3} b ^{4}} - \frac{9 b ^{2}}{24 a ^{3} b ^{4}}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{4 a ^{2} - 9 b ^{2}}{24 a ^{3} b ^{4}}

x^{2} - 8 x + 20 = 0

b^{2} + 9 b + 17 = 7

x^{2} = - 32

8 - ∣ 2 x - 3 ∣ = 5

(x^{- 5} y^{\frac{1}{3}})^{- \frac{3}{5}}

What is 1/(6ab^4)-3/(8a^3b^2) ?
The solution to 1/(6ab^4)-3/(8a^3b^2) is (4a^2-9b^2)/(24a^3b^4)